What are the solutions to the equation -3x^2+2x-4=0 ?

The solutions to the equation -3x^2+2x-4=0 are x= 1/3-i(sqrt(11))/3 ,x= 1/3+i(sqrt(11))/3

Find the zeros of -3x^2+2x-4=0

The zeros of -3x^2+2x-4=0 are x= 1/3-i(sqrt(11))/3 ,x= 1/3+i(sqrt(11))/3

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- 3 x^{2} + 2 x - 4 = 0

x = \frac{1}{3} - i \frac{11}{3}, x = \frac{1}{3} + i \frac{11}{3}

Solution steps

- 3 x^{2} + 2 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 3 ) ( - 4 )}{2 ( - 3 )}

Simplify

2^{2} - 4 (- 3) (- 4) : 211 i

x_{1, 2} = \frac{- 2 \pm 2 11 i}{2 ( - 3 )}

Separate the solutions

x_{1} = \frac{- 2 + 2 11 i}{2 ( - 3 )}, x_{2} = \frac{- 2 - 2 11 i}{2 ( - 3 )}

x = \frac{- 2 + 2 11 i}{2 ( - 3 )} : \frac{1}{3} - i \frac{11}{3}

x = \frac{- 2 - 2 11 i}{2 ( - 3 )} : \frac{1}{3} + i \frac{11}{3}

The solutions to the quadratic equation are:

x = \frac{1}{3} - i \frac{11}{3}, x = \frac{1}{3} + i \frac{11}{3}

x^{2} + 16 = 7 x

x^{2} + 10 x - 13 = 0

x^{2} + 10 x - 16 = 0

x^{2} + 15 x - 36 = 0

6 w^{2} - 13 w + 5 = 0

What are the solutions to the equation -3x^2+2x-4=0 ?
The solutions to the equation -3x^2+2x-4=0 are x= 1/3-i(sqrt(11))/3 ,x= 1/3+i(sqrt(11))/3
Find the zeros of -3x^2+2x-4=0
The zeros of -3x^2+2x-4=0 are x= 1/3-i(sqrt(11))/3 ,x= 1/3+i(sqrt(11))/3