What are the solutions to the equation 4x^2+22x-30=0 ?

The solutions to the equation 4x^2+22x-30=0 are x=(-11+sqrt(241))/4 ,x=-(11+sqrt(241))/4

Find the zeros of 4x^2+22x-30=0

The zeros of 4x^2+22x-30=0 are x=(-11+sqrt(241))/4 ,x=-(11+sqrt(241))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 x^{2} + 22 x - 30 = 0

x = \frac{- 11 + 241}{4}, x = - \frac{11 + 241}{4}

Decimal Notation

x = 1.13104 \dots, x = - 6.63104 \dots

Solution steps

4 x^{2} + 22 x - 30 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 22 \pm 2 2 ^{2} - 4 \cdot 4 ( - 30 )}{2 \cdot 4}

2 2^{2} - 4 \cdot 4 (- 30) = 2241

x_{1, 2} = \frac{- 22 \pm 2 241}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 22 + 2 241}{2 \cdot 4}, x_{2} = \frac{- 22 - 2 241}{2 \cdot 4}

x = \frac{- 22 + 2 241}{2 \cdot 4} : \frac{- 11 + 241}{4}

x = \frac{- 22 - 2 241}{2 \cdot 4} : - \frac{11 + 241}{4}

The solutions to the quadratic equation are:

x = \frac{- 11 + 241}{4}, x = - \frac{11 + 241}{4}

2 x^{2} - 12 x = 64

x^{2} + 13 = 8 x + 37

x^{2} - 12 x + 36 = 44

(x + 8) (2 x - 10) = 0

x^{2} + 6 x - 9 = 0

What are the solutions to the equation 4x^2+22x-30=0 ?
The solutions to the equation 4x^2+22x-30=0 are x=(-11+sqrt(241))/4 ,x=-(11+sqrt(241))/4
Find the zeros of 4x^2+22x-30=0
The zeros of 4x^2+22x-30=0 are x=(-11+sqrt(241))/4 ,x=-(11+sqrt(241))/4