What are the solutions to the equation x^2+7x+25=0 ?

The solutions to the equation x^2+7x+25=0 are x=-7/2+i(sqrt(51))/2 ,x=-7/2-i(sqrt(51))/2

Find the zeros of x^2+7x+25=0

The zeros of x^2+7x+25=0 are x=-7/2+i(sqrt(51))/2 ,x=-7/2-i(sqrt(51))/2

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x^{2} + 7 x + 25 = 0

x = - \frac{7}{2} + i \frac{51}{2}, x = - \frac{7}{2} - i \frac{51}{2}

Solution steps

x^{2} + 7 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 7 \pm 7 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

Simplify

7^{2} - 4 \cdot 1 \cdot 25 : 51 i

x_{1, 2} = \frac{- 7 \pm 51 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 7 + 51 i}{2 \cdot 1}, x_{2} = \frac{- 7 - 51 i}{2 \cdot 1}

x = \frac{- 7 + 51 i}{2 \cdot 1} : - \frac{7}{2} + i \frac{51}{2}

x = \frac{- 7 - 51 i}{2 \cdot 1} : - \frac{7}{2} - i \frac{51}{2}

The solutions to the quadratic equation are:

x = - \frac{7}{2} + i \frac{51}{2}, x = - \frac{7}{2} - i \frac{51}{2}

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3 x^{2} + 14 x - 24 = 0

x^{2} + 4 x = 0

2 x^{2} + 4 x - 6 = 0

What are the solutions to the equation x^2+7x+25=0 ?
The solutions to the equation x^2+7x+25=0 are x=-7/2+i(sqrt(51))/2 ,x=-7/2-i(sqrt(51))/2
Find the zeros of x^2+7x+25=0
The zeros of x^2+7x+25=0 are x=-7/2+i(sqrt(51))/2 ,x=-7/2-i(sqrt(51))/2