What are the solutions to the equation 6x^2+11x=35 ?

The solutions to the equation 6x^2+11x=35 are x= 5/3 ,x=-7/2

Find the zeros of 6x^2+11x=35

The zeros of 6x^2+11x=35 are x= 5/3 ,x=-7/2

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6 x^{2} + 11 x = 35

x = \frac{5}{3}, x = - \frac{7}{2}

Decimal Notation

x = 1.66666 \dots, x = - 3.5

Solution steps

6 x^{2} + 11 x = 35

Move

35

to the left side

6 x^{2} + 11 x - 35 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 6 ( - 35 )}{2 \cdot 6}

1 1^{2} - 4 \cdot 6 (- 35) = 31

x_{1, 2} = \frac{- 11 \pm 31}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 11 + 31}{2 \cdot 6}, x_{2} = \frac{- 11 - 31}{2 \cdot 6}

x = \frac{- 11 + 31}{2 \cdot 6} : \frac{5}{3}

x = \frac{- 11 - 31}{2 \cdot 6} : - \frac{7}{2}

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = - \frac{7}{2}

x^{2} + 12 x - 28 = 0

- 2 x^{2} + 50 = 0

x^{2} - 6 x + 2 = 0

7 x^{2} - 6 x - 4 = - x + 4 x^{2}

x^{2} - 6 x + 7 = 0

What are the solutions to the equation 6x^2+11x=35 ?
The solutions to the equation 6x^2+11x=35 are x= 5/3 ,x=-7/2
Find the zeros of 6x^2+11x=35
The zeros of 6x^2+11x=35 are x= 5/3 ,x=-7/2