What are the solutions to the equation quadraticformula x^2+4x-1=0 ?

The solutions to the equation quadraticformula x^2+4x-1=0 are x=-2+sqrt(5),x=-2-sqrt(5)

Find the zeros of quadraticformula x^2+4x-1=0

The zeros of quadraticformula x^2+4x-1=0 are x=-2+sqrt(5),x=-2-sqrt(5)

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x^{2} + 4 x - 1 = 0

x = - 2 + 5, x = - 2 - 5

Decimal Notation

x = 0.23606 \dots, x = - 4.23606 \dots

Solution steps

x^{2} + 4 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

4^{2} - 4 \cdot 1 \cdot (- 1) = 25

x_{1, 2} = \frac{- 4 \pm 2 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 4 + 2 5}{2 \cdot 1}, x_{2} = \frac{- 4 - 2 5}{2 \cdot 1}

x = \frac{- 4 + 2 5}{2 \cdot 1} : - 2 + 5

x = \frac{- 4 - 2 5}{2 \cdot 1} : - 2 - 5

The solutions to the quadratic equation are:

x = - 2 + 5, x = - 2 - 5

25 x^{2} + 20 x + 4 = 75

6 x^{2} + x^{2} + 1 = 0

5 x^{2} - 2 x = 1

2 c^{2} + 14 c + 24 = 0

x^{2} - 5 x - 11 = 0

What are the solutions to the equation quadraticformula x^2+4x-1=0 ?
The solutions to the equation quadraticformula x^2+4x-1=0 are x=-2+sqrt(5),x=-2-sqrt(5)
Find the zeros of quadraticformula x^2+4x-1=0
The zeros of quadraticformula x^2+4x-1=0 are x=-2+sqrt(5),x=-2-sqrt(5)