What are the solutions to the equation 14/5 =x+x^2 ?

The solutions to the equation 14/5 =x+x^2 are x=(-5+sqrt(305))/(10),x=(-5-sqrt(305))/(10)

Find the zeros of 14/5 =x+x^2

The zeros of 14/5 =x+x^2 are x=(-5+sqrt(305))/(10),x=(-5-sqrt(305))/(10)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

\frac{14}{5} = x + x^{2}

x = \frac{- 5 + 305}{10}, x = \frac{- 5 - 305}{10}

Decimal Notation

x = 1.24642 \dots, x = - 2.24642 \dots

Solution steps

\frac{14}{5} = x + x^{2}

Multiply both sides by

5

14 = 5 x + 5 x^{2}

Switch sides

5 x + 5 x^{2} = 14

Move

14

to the left side

5 x + 5 x^{2} - 14 = 0

Write in the standard form

a x^{2} + b x + c = 0

5 x^{2} + 5 x - 14 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 5 ( - 14 )}{2 \cdot 5}

5^{2} - 4 \cdot 5 (- 14) = 305

x_{1, 2} = \frac{- 5 \pm 305}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 5 + 305}{2 \cdot 5}, x_{2} = \frac{- 5 - 305}{2 \cdot 5}

x = \frac{- 5 + 305}{2 \cdot 5} : \frac{- 5 + 305}{10}

x = \frac{- 5 - 305}{2 \cdot 5} : \frac{- 5 - 305}{10}

The solutions to the quadratic equation are:

x = \frac{- 5 + 305}{10}, x = \frac{- 5 - 305}{10}

3 y^{2} - 2 y = 0

6 x^{2} = 864

5 x^{2} + 10 x + 15 = 0

x^{2} + 20 x - 6 = 0

p, 3 p^{2} + 12 p = 6

What are the solutions to the equation 14/5 =x+x^2 ?
The solutions to the equation 14/5 =x+x^2 are x=(-5+sqrt(305))/(10),x=(-5-sqrt(305))/(10)
Find the zeros of 14/5 =x+x^2
The zeros of 14/5 =x+x^2 are x=(-5+sqrt(305))/(10),x=(-5-sqrt(305))/(10)