What are the solutions to the equation solvefor x,x^2+10x+25=0 ?

The solutions to the equation solvefor x,x^2+10x+25=0 are x=-5

Find the zeros of solvefor x,x^2+10x+25=0

The zeros of solvefor x,x^2+10x+25=0 are x=-5

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x, x^{2} + 10 x + 25 = 0

x = - 5

Solution steps

x^{2} + 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 25 = 0

x_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 1}

x = \frac{- 10}{2 \cdot 1}

\frac{- 10}{2 \cdot 1} = - 5

x = - 5

The solution to the quadratic equation is:

x = - 5

x, (x + 2)^{2} - (y + 5)^{2} = 0

x^{2} + 6 x - 216 = 0

9 x^{2} - 12 + 4 = 0

(x) = x^{2} + 6 x + 8

p^{2} - 121 = 0

What are the solutions to the equation solvefor x,x^2+10x+25=0 ?
The solutions to the equation solvefor x,x^2+10x+25=0 are x=-5
Find the zeros of solvefor x,x^2+10x+25=0
The zeros of solvefor x,x^2+10x+25=0 are x=-5