What are the solutions to the equation x^2+0.9x-7.92=0 ?

The solutions to the equation x^2+0.9x-7.92=0 are x= 12/5 ,x=-33/10

Find the zeros of x^2+0.9x-7.92=0

The zeros of x^2+0.9x-7.92=0 are x= 12/5 ,x=-33/10

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x^{2} + 0.9 x - 7.92 = 0

x = \frac{12}{5}, x = - \frac{33}{10}

Decimal Notation

x = 2.4, x = - 3.3

Solution steps

x^{2} + 0.9 x - 7.92 = 0

Multiply both sides by

100

100 x^{2} + 90 x - 792 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 90 \pm 9 0 ^{2} - 4 \cdot 100 ( - 792 )}{2 \cdot 100}

9 0^{2} - 4 \cdot 100 (- 792) = 570

x_{1, 2} = \frac{- 90 \pm 570}{2 \cdot 100}

Separate the solutions

x_{1} = \frac{- 90 + 570}{2 \cdot 100}, x_{2} = \frac{- 90 - 570}{2 \cdot 100}

x = \frac{- 90 + 570}{2 \cdot 100} : \frac{12}{5}

x = \frac{- 90 - 570}{2 \cdot 100} : - \frac{33}{10}

The solutions to the quadratic equation are:

x = \frac{12}{5}, x = - \frac{33}{10}

y^{2} + 4 y - 6 = 0

12 x^{2} - 288 x + 1152 = 0

(X + 6) (X - 6) = 13

x^{2} + 17 x + 12 = 0

23 x = - 15 x^{2} - 6

What are the solutions to the equation x^2+0.9x-7.92=0 ?
The solutions to the equation x^2+0.9x-7.92=0 are x= 12/5 ,x=-33/10
Find the zeros of x^2+0.9x-7.92=0
The zeros of x^2+0.9x-7.92=0 are x= 12/5 ,x=-33/10