What are the solutions to the equation 2x(x+3)+2(x+3)=0 ?

The solutions to the equation 2x(x+3)+2(x+3)=0 are x=-1,x=-3

Find the zeros of 2x(x+3)+2(x+3)=0

The zeros of 2x(x+3)+2(x+3)=0 are x=-1,x=-3

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2 x (x + 3) + 2 (x + 3) = 0

x = - 1, x = - 3

Solution steps

2 x (x + 3) + 2 (x + 3) = 0

Expand

2 x (x + 3) + 2 (x + 3) : 2 x^{2} + 8 x + 6

2 x^{2} + 8 x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

8^{2} - 4 \cdot 2 \cdot 6 = 4

x_{1, 2} = \frac{- 8 \pm 4}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 8 + 4}{2 \cdot 2}, x_{2} = \frac{- 8 - 4}{2 \cdot 2}

x = \frac{- 8 + 4}{2 \cdot 2} : - 1

x = \frac{- 8 - 4}{2 \cdot 2} : - 3

The solutions to the quadratic equation are:

x = - 1, x = - 3

12 x^{2} + 24 x - 4 = 0

9 x + 1 = 3 (x^{2} - 5) - (x - 3) (x + 2)

0 = 3 x^{2} + 8 x - 11

2 x^{2} - 5 x = - 9

2 x^{2} - 5 x = 2 x

What are the solutions to the equation 2x(x+3)+2(x+3)=0 ?
The solutions to the equation 2x(x+3)+2(x+3)=0 are x=-1,x=-3
Find the zeros of 2x(x+3)+2(x+3)=0
The zeros of 2x(x+3)+2(x+3)=0 are x=-1,x=-3