What are the solutions to the equation 4x^2-x+8=0 ?

The solutions to the equation 4x^2-x+8=0 are x= 1/8+i(sqrt(127))/8 ,x= 1/8-i(sqrt(127))/8

Find the zeros of 4x^2-x+8=0

The zeros of 4x^2-x+8=0 are x= 1/8+i(sqrt(127))/8 ,x= 1/8-i(sqrt(127))/8

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4 x^{2} - x + 8 = 0

x = \frac{1}{8} + i \frac{127}{8}, x = \frac{1}{8} - i \frac{127}{8}

Solution steps

4 x^{2} - x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 \cdot 8}{2 \cdot 4}

Simplify

(- 1)^{2} - 4 \cdot 4 \cdot 8 : 127 i

x_{1, 2} = \frac{- ( - 1 ) \pm 127 i}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 127 i}{2 \cdot 4}, x_{2} = \frac{- ( - 1 ) - 127 i}{2 \cdot 4}

x = \frac{- ( - 1 ) + 127 i}{2 \cdot 4} : \frac{1}{8} + i \frac{127}{8}

x = \frac{- ( - 1 ) - 127 i}{2 \cdot 4} : \frac{1}{8} - i \frac{127}{8}

The solutions to the quadratic equation are:

x = \frac{1}{8} + i \frac{127}{8}, x = \frac{1}{8} - i \frac{127}{8}

x, x^{2} y + 5 x y + 4 y = 0

x^{2} - 14 x - 48 = 0

x^{2} + 4 x + 2

x^{2} + 4 x - 6

x^{2} - 2 x + 1 = 0

What are the solutions to the equation 4x^2-x+8=0 ?
The solutions to the equation 4x^2-x+8=0 are x= 1/8+i(sqrt(127))/8 ,x= 1/8-i(sqrt(127))/8
Find the zeros of 4x^2-x+8=0
The zeros of 4x^2-x+8=0 are x= 1/8+i(sqrt(127))/8 ,x= 1/8-i(sqrt(127))/8