What are the solutions to the equation 9x^2+36x-45=0 ?

The solutions to the equation 9x^2+36x-45=0 are x=1,x=-5

Find the zeros of 9x^2+36x-45=0

The zeros of 9x^2+36x-45=0 are x=1,x=-5

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9 x^{2} + 36 x - 45 = 0

x = 1, x = - 5

Solution steps

9 x^{2} + 36 x - 45 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 36 \pm 3 6 ^{2} - 4 \cdot 9 ( - 45 )}{2 \cdot 9}

3 6^{2} - 4 \cdot 9 (- 45) = 54

x_{1, 2} = \frac{- 36 \pm 54}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 36 + 54}{2 \cdot 9}, x_{2} = \frac{- 36 - 54}{2 \cdot 9}

x = \frac{- 36 + 54}{2 \cdot 9} : 1

x = \frac{- 36 - 54}{2 \cdot 9} : - 5

The solutions to the quadratic equation are:

x = 1, x = - 5

5 x^{2} - 7 x - 6 = 0

3 (2 x - 1)^{2} + 27 = 36 x^{2} - 36 x + 36

x^{2} - x - 5 x + 10 = 2

2 x^{2} - 12 x + 12 = 0

6 x^{2} + 2 x - \frac{3}{2} = 0

What are the solutions to the equation 9x^2+36x-45=0 ?
The solutions to the equation 9x^2+36x-45=0 are x=1,x=-5
Find the zeros of 9x^2+36x-45=0
The zeros of 9x^2+36x-45=0 are x=1,x=-5