What are the solutions to the equation s^2+12s+25=0 ?

The solutions to the equation s^2+12s+25=0 are s=-6+sqrt(11),s=-6-sqrt(11)

Find the zeros of s^2+12s+25=0

The zeros of s^2+12s+25=0 are s=-6+sqrt(11),s=-6-sqrt(11)

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s^{2} + 12 s + 25 = 0

s = - 6 + 11, s = - 6 - 11

Decimal Notation

s = - 2.68337 \dots, s = - 9.31662 \dots

Solution steps

s^{2} + 12 s + 25 = 0

Solve with the quadratic formula

s_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 2^{2} - 4 \cdot 1 \cdot 25 = 211

s_{1, 2} = \frac{- 12 \pm 2 11}{2 \cdot 1}

Separate the solutions

s_{1} = \frac{- 12 + 2 11}{2 \cdot 1}, s_{2} = \frac{- 12 - 2 11}{2 \cdot 1}

s = \frac{- 12 + 2 11}{2 \cdot 1} : - 6 + 11

s = \frac{- 12 - 2 11}{2 \cdot 1} : - 6 - 11

The solutions to the quadratic equation are:

s = - 6 + 11, s = - 6 - 11

3 + 2 x^{2} - 3 x = 7 + 6 x

x^{2} + 16 x + 5 = 9

20 x^{2} - x - 1 = 0

3 x^{2} = 2 + x

8 m = m^{2} + 15

What are the solutions to the equation s^2+12s+25=0 ?
The solutions to the equation s^2+12s+25=0 are s=-6+sqrt(11),s=-6-sqrt(11)
Find the zeros of s^2+12s+25=0
The zeros of s^2+12s+25=0 are s=-6+sqrt(11),s=-6-sqrt(11)