What are the solutions to the equation 8m=m^2+15 ?

The solutions to the equation 8m=m^2+15 are m=5,m=3

Find the zeros of 8m=m^2+15

The zeros of 8m=m^2+15 are m=5,m=3

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8 m = m^{2} + 15

m = 5, m = 3

Solution steps

8 m = m^{2} + 15

Switch sides

m^{2} + 15 = 8 m

Move

8 m

to the left side

m^{2} + 15 - 8 m = 0

Write in the standard form

a x^{2} + b x + c = 0

m^{2} - 8 m + 15 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 15}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot 15 = 2

m_{1, 2} = \frac{- ( - 8 ) \pm 2}{2 \cdot 1}

Separate the solutions

m_{1} = \frac{- ( - 8 ) + 2}{2 \cdot 1}, m_{2} = \frac{- ( - 8 ) - 2}{2 \cdot 1}

m = \frac{- ( - 8 ) + 2}{2 \cdot 1} : 5

m = \frac{- ( - 8 ) - 2}{2 \cdot 1} : 3

The solutions to the quadratic equation are:

m = 5, m = 3

9 n^{2} - 14 = 0

9 x^{2} - 6 x + 3 = 0

- 2.5 x^{2} + 0.9 = 0

x^{2} - x - 1 = 0

3 x^{2} + 9 x + 5

What are the solutions to the equation 8m=m^2+15 ?
The solutions to the equation 8m=m^2+15 are m=5,m=3
Find the zeros of 8m=m^2+15
The zeros of 8m=m^2+15 are m=5,m=3