What are the solutions to the equation -2.5x^2+0.9=0 ?

The solutions to the equation -2.5x^2+0.9=0 are x= 3/5 ,x=-3/5

Find the zeros of -2.5x^2+0.9=0

The zeros of -2.5x^2+0.9=0 are x= 3/5 ,x=-3/5

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- 2.5 x^{2} + 0.9 = 0

x = \frac{3}{5}, x = - \frac{3}{5}

Decimal Notation

x = 0.6, x = - 0.6

Solution steps

- 2.5 x^{2} + 0.9 = 0

Move

0.9

to the right side

- 2.5 x^{2} = - 0.9

Divide both sides by

- 2.5

x^{2} = 0.36

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 0.36, x = - 0.36

0.36 = \frac{3}{5}

- 0.36 = - \frac{3}{5}

x = \frac{3}{5}, x = - \frac{3}{5}

x^{2} - x - 1 = 0

3 x^{2} + 9 x + 5

x, x^{2} + y^{2} + (z - 5)^{2} = 25

6 x^{2} - 16 = 0

2 r^{2} + 6 r + 4 = 0

What are the solutions to the equation -2.5x^2+0.9=0 ?
The solutions to the equation -2.5x^2+0.9=0 are x= 3/5 ,x=-3/5
Find the zeros of -2.5x^2+0.9=0
The zeros of -2.5x^2+0.9=0 are x= 3/5 ,x=-3/5