What are the solutions to the equation b(b-15)=30-2b ?

The solutions to the equation b(b-15)=30-2b are b=15,b=-2

Find the zeros of b(b-15)=30-2b

The zeros of b(b-15)=30-2b are b=15,b=-2

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b (b - 15) = 30 - 2 b

b = 15, b = - 2

Solution steps

b (b - 15) = 30 - 2 b

Expand

b (b - 15) : b^{2} - 15 b

b^{2} - 15 b = 30 - 2 b

Move

2 b

to the left side

b^{2} - 13 b = 30

Move

30

to the left side

b^{2} - 13 b - 30 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 1 \cdot ( - 30 )}{2 \cdot 1}

(- 13)^{2} - 4 \cdot 1 \cdot (- 30) = 17

b_{1, 2} = \frac{- ( - 13 ) \pm 17}{2 \cdot 1}

Separate the solutions

b_{1} = \frac{- ( - 13 ) + 17}{2 \cdot 1}, b_{2} = \frac{- ( - 13 ) - 17}{2 \cdot 1}

b = \frac{- ( - 13 ) + 17}{2 \cdot 1} : 15

b = \frac{- ( - 13 ) - 17}{2 \cdot 1} : - 2

The solutions to the quadratic equation are:

b = 15, b = - 2

(x - 9)^{2} = - 1

x^{2} + 10 x + 31 = 7

x^{2} - 3 x = 4 x^{2}

4 x^{2} - 4 x - 15 = 0

x, x^{2} + 4 x - 5 = 0

What are the solutions to the equation b(b-15)=30-2b ?
The solutions to the equation b(b-15)=30-2b are b=15,b=-2
Find the zeros of b(b-15)=30-2b
The zeros of b(b-15)=30-2b are b=15,b=-2