What are the solutions to the equation factor 4x^2-4x-15=0 ?

The solutions to the equation factor 4x^2-4x-15=0 are x=-3/2 ,x= 5/2

Find the zeros of factor 4x^2-4x-15=0

The zeros of factor 4x^2-4x-15=0 are x=-3/2 ,x= 5/2

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4 x^{2} - 4 x - 15 = 0

x = - \frac{3}{2}, x = \frac{5}{2}

Decimal Notation

x = - 1.5, x = 2.5

Solution steps

4 x^{2} - 4 x - 15 = 0

Factor

4 x^{2} - 4 x - 15 : (2 x + 3) (2 x - 5)

(2 x + 3) (2 x - 5) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x + 3 = 0 or 2 x - 5 = 0

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

Solve

2 x - 5 = 0 : x = \frac{5}{2}

The solutions to the quadratic equation are:

x = - \frac{3}{2}, x = \frac{5}{2}

x, x^{2} + 4 x - 5 = 0

x (x - 7) = 44

x^{2} - x - 18 = - 4 x - 4 x

16 x^{2} - 4 x + 3 = 0

2 x^{2} + x - 1 = 0

What are the solutions to the equation factor 4x^2-4x-15=0 ?
The solutions to the equation factor 4x^2-4x-15=0 are x=-3/2 ,x= 5/2
Find the zeros of factor 4x^2-4x-15=0
The zeros of factor 4x^2-4x-15=0 are x=-3/2 ,x= 5/2