What are the solutions to the equation 2x^2-mx+(m+6)=0 ?

The solutions to the equation 2x^2-mx+(m+6)=0 are x=(m+sqrt(m^2-8(m+6)))/4 ,x=(m-sqrt(m^2-8(m+6)))/4

Find the zeros of 2x^2-mx+(m+6)=0

The zeros of 2x^2-mx+(m+6)=0 are x=(m+sqrt(m^2-8(m+6)))/4 ,x=(m-sqrt(m^2-8(m+6)))/4

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2 x^{2} - m x + (m + 6) = 0

x = \frac{m + m ^{2} - 8 ( m + 6 )}{4}, x = \frac{m - m ^{2} - 8 ( m + 6 )}{4}

Solution steps

2 x^{2} - m x + (m + 6) = 0

Refine

2 x^{2} - m x + m + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - m ) \pm ( - m ) ^{2} - 4 \cdot 2 ( m + 6 )}{2 \cdot 2}

Simplify

(- m)^{2} - 4 \cdot 2 (m + 6) : m^{2} - 8 (m + 6)

x_{1, 2} = \frac{- ( - m ) \pm m ^{2} - 8 ( m + 6 )}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - m ) + m ^{2} - 8 ( m + 6 )}{2 \cdot 2}, x_{2} = \frac{- ( - m ) - m ^{2} - 8 ( m + 6 )}{2 \cdot 2}

x = \frac{- ( - m ) + m ^{2} - 8 ( m + 6 )}{2 \cdot 2} : \frac{m + m ^{2} - 8 ( m + 6 )}{4}

x = \frac{- ( - m ) - m ^{2} - 8 ( m + 6 )}{2 \cdot 2} : \frac{m - m ^{2} - 8 ( m + 6 )}{4}

The solutions to the quadratic equation are:

x = \frac{m + m ^{2} - 8 ( m + 6 )}{4}, x = \frac{m - m ^{2} - 8 ( m + 6 )}{4}

x, 3 x^{2} - 4 x y - 4 y^{2} + 16 x + 16 y - 12 = 0

2 x^{2} + 15 x + 38 = x^{2}

r^{2} + 6 r = 0

2 x^{2} = 11 x - 12

0 = - 16 t^{2} + 400

What are the solutions to the equation 2x^2-mx+(m+6)=0 ?
The solutions to the equation 2x^2-mx+(m+6)=0 are x=(m+sqrt(m^2-8(m+6)))/4 ,x=(m-sqrt(m^2-8(m+6)))/4
Find the zeros of 2x^2-mx+(m+6)=0
The zeros of 2x^2-mx+(m+6)=0 are x=(m+sqrt(m^2-8(m+6)))/4 ,x=(m-sqrt(m^2-8(m+6)))/4