What are the solutions to the equation 0=-16t^2+400 ?

The solutions to the equation 0=-16t^2+400 are t=5,t=-5

Find the zeros of 0=-16t^2+400

The zeros of 0=-16t^2+400 are t=5,t=-5

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0 = - 16 t^{2} + 400

t = 5, t = - 5

Solution steps

0 = - 16 t^{2} + 400

Switch sides

- 16 t^{2} + 400 = 0

Move

400

to the right side

- 16 t^{2} = - 400

Divide both sides by

- 16

t^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 25, t = - 25

25 = 5

- 25 = - 5

t = 5, t = - 5

4 1^{2} = 9^{2} + x^{2}

6 x^{2} + 4 x + 11 = 0

18 q^{2} - 32 q = 7

x^{2} - 8 x + 4 = 0

x, 9 x^{2} - 16 y^{2} - 18 x - 64 y - 55 = 0

What are the solutions to the equation 0=-16t^2+400 ?
The solutions to the equation 0=-16t^2+400 are t=5,t=-5
Find the zeros of 0=-16t^2+400
The zeros of 0=-16t^2+400 are t=5,t=-5