What are the solutions to the equation 2x^2+x-12=0 ?

The solutions to the equation 2x^2+x-12=0 are x=(-1+sqrt(97))/4 ,x=(-1-sqrt(97))/4

Find the zeros of 2x^2+x-12=0

The zeros of 2x^2+x-12=0 are x=(-1+sqrt(97))/4 ,x=(-1-sqrt(97))/4

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2 x^{2} + x - 12 = 0

x = \frac{- 1 + 97}{4}, x = \frac{- 1 - 97}{4}

Decimal Notation

x = 2.21221 \dots, x = - 2.71221 \dots

Solution steps

2 x^{2} + x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

1^{2} - 4 \cdot 2 (- 12) = 97

x_{1, 2} = \frac{- 1 \pm 97}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- 1 + 97}{2 \cdot 2}, x_{2} = \frac{- 1 - 97}{2 \cdot 2}

x = \frac{- 1 + 97}{2 \cdot 2} : \frac{- 1 + 97}{4}

x = \frac{- 1 - 97}{2 \cdot 2} : \frac{- 1 - 97}{4}

The solutions to the quadratic equation are:

x = \frac{- 1 + 97}{4}, x = \frac{- 1 - 97}{4}

x (5 x - 1) = 0

x^{2} - 5 = - 4 x

5 x^{2} - 60 = 20

3 x^{2} = - 4 + 8 x

(x - 1)^{2} + 11 x - 199 = 3 x^{2} - (x - 2)^{2}

What are the solutions to the equation 2x^2+x-12=0 ?
The solutions to the equation 2x^2+x-12=0 are x=(-1+sqrt(97))/4 ,x=(-1-sqrt(97))/4
Find the zeros of 2x^2+x-12=0
The zeros of 2x^2+x-12=0 are x=(-1+sqrt(97))/4 ,x=(-1-sqrt(97))/4