What are the solutions to the equation x^2+16x-9=0 ?

The solutions to the equation x^2+16x-9=0 are x=-8+sqrt(73),x=-8-sqrt(73)

Find the zeros of x^2+16x-9=0

The zeros of x^2+16x-9=0 are x=-8+sqrt(73),x=-8-sqrt(73)

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x^{2} + 16 x - 9 = 0

x = - 8 + 73, x = - 8 - 73

Decimal Notation

x = 0.54400 \dots, x = - 16.54400 \dots

Solution steps

x^{2} + 16 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 16 \pm 1 6 ^{2} - 4 \cdot 1 \cdot ( - 9 )}{2 \cdot 1}

1 6^{2} - 4 \cdot 1 \cdot (- 9) = 273

x_{1, 2} = \frac{- 16 \pm 2 73}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 16 + 2 73}{2 \cdot 1}, x_{2} = \frac{- 16 - 2 73}{2 \cdot 1}

x = \frac{- 16 + 2 73}{2 \cdot 1} : - 8 + 73

x = \frac{- 16 - 2 73}{2 \cdot 1} : - 8 - 73

The solutions to the quadratic equation are:

x = - 8 + 73, x = - 8 - 73

x^{2} + 8 x + c

- 5 x - 13 + 7 x^{2} = 3 x^{2}

2 x^{2} + x - 20 = 0

t, s = \frac{1}{2} g t^{2} + v t

X^{2} - X - 2 = 0

What are the solutions to the equation x^2+16x-9=0 ?
The solutions to the equation x^2+16x-9=0 are x=-8+sqrt(73),x=-8-sqrt(73)
Find the zeros of x^2+16x-9=0
The zeros of x^2+16x-9=0 are x=-8+sqrt(73),x=-8-sqrt(73)