What are the solutions to the equation 128-6x^2=0 ?

The solutions to the equation 128-6x^2=0 are x= 8/(sqrt(3)),x=-8/(sqrt(3))

Find the zeros of 128-6x^2=0

The zeros of 128-6x^2=0 are x= 8/(sqrt(3)),x=-8/(sqrt(3))

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128 - 6 x^{2} = 0

x = \frac{8}{3}, x = - \frac{8}{3}

Decimal Notation

x = 4.61880 \dots, x = - 4.61880 \dots

Solution steps

128 - 6 x^{2} = 0

Move

128

to the right side

- 6 x^{2} = - 128

Divide both sides by

- 6

x^{2} = \frac{64}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = \frac{64}{3}, x = - \frac{64}{3}

\frac{64}{3} = \frac{8}{3}

- \frac{64}{3} = - \frac{8}{3}

x = \frac{8}{3}, x = - \frac{8}{3}

x^{2} = 1 0^{2} + 2 4^{2}

(x + 1) (x + 6) = - 6

(x - 2)^{2} - 10 (x - 2) + 9 = 0

1650 + 45 x + x^{2} = 130 x

2 x^{2} + 2 = 34

What are the solutions to the equation 128-6x^2=0 ?
The solutions to the equation 128-6x^2=0 are x= 8/(sqrt(3)),x=-8/(sqrt(3))
Find the zeros of 128-6x^2=0
The zeros of 128-6x^2=0 are x= 8/(sqrt(3)),x=-8/(sqrt(3))