What are the solutions to the equation 1650+45x+x^2=130x ?

The solutions to the equation 1650+45x+x^2=130x are x=55,x=30

Find the zeros of 1650+45x+x^2=130x

The zeros of 1650+45x+x^2=130x are x=55,x=30

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1650 + 45 x + x^{2} = 130 x

x = 55, x = 30

Solution steps

1650 + 45 x + x^{2} = 130 x

Move

130 x

to the left side

x^{2} - 85 x + 1650 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 85 ) \pm ( - 85 ) ^{2} - 4 \cdot 1 \cdot 1650}{2 \cdot 1}

(- 85)^{2} - 4 \cdot 1 \cdot 1650 = 25

x_{1, 2} = \frac{- ( - 85 ) \pm 25}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 85 ) + 25}{2 \cdot 1}, x_{2} = \frac{- ( - 85 ) - 25}{2 \cdot 1}

x = \frac{- ( - 85 ) + 25}{2 \cdot 1} : 55

x = \frac{- ( - 85 ) - 25}{2 \cdot 1} : 30

The solutions to the quadratic equation are:

x = 55, x = 30

2 x^{2} + 2 = 34

500 x^{2} - 2500 x + 35000 = 0

0 = 6 x^{2} - 6

x^{2} = 9 x - 14

0 = - 4.9 t^{2} + 40 t

What are the solutions to the equation 1650+45x+x^2=130x ?
The solutions to the equation 1650+45x+x^2=130x are x=55,x=30
Find the zeros of 1650+45x+x^2=130x
The zeros of 1650+45x+x^2=130x are x=55,x=30