What are the solutions to the equation 8b^2+59b+21=0 ?

The solutions to the equation 8b^2+59b+21=0 are b=-3/8 ,b=-7

Find the zeros of 8b^2+59b+21=0

The zeros of 8b^2+59b+21=0 are b=-3/8 ,b=-7

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8 b^{2} + 59 b + 21 = 0

b = - \frac{3}{8}, b = - 7

Decimal Notation

b = - 0.375, b = - 7

Solution steps

8 b^{2} + 59 b + 21 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- 59 \pm 5 9 ^{2} - 4 \cdot 8 \cdot 21}{2 \cdot 8}

5 9^{2} - 4 \cdot 8 \cdot 21 = 53

b_{1, 2} = \frac{- 59 \pm 53}{2 \cdot 8}

Separate the solutions

b_{1} = \frac{- 59 + 53}{2 \cdot 8}, b_{2} = \frac{- 59 - 53}{2 \cdot 8}

b = \frac{- 59 + 53}{2 \cdot 8} : - \frac{3}{8}

b = \frac{- 59 - 53}{2 \cdot 8} : - 7

The solutions to the quadratic equation are:

b = - \frac{3}{8}, b = - 7

(x^{2} - 9 x) + (11 x + 12) = 180

b^{2} + 19 b

x^{2} - 6 x = 0

x, \frac{x ^{2}}{4} + \frac{y ^{2}}{9} - \frac{z ^{2}}{25} = 0

x, z = x^{2} - 4 x y + y^{2} - 6 y

What are the solutions to the equation 8b^2+59b+21=0 ?
The solutions to the equation 8b^2+59b+21=0 are b=-3/8 ,b=-7
Find the zeros of 8b^2+59b+21=0
The zeros of 8b^2+59b+21=0 are b=-3/8 ,b=-7