What are the solutions to the equation 3x^2-15x+186=0 ?

The solutions to the equation 3x^2-15x+186=0 are x= 5/2+i(sqrt(223))/2 ,x= 5/2-i(sqrt(223))/2

Find the zeros of 3x^2-15x+186=0

The zeros of 3x^2-15x+186=0 are x= 5/2+i(sqrt(223))/2 ,x= 5/2-i(sqrt(223))/2

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3 x^{2} - 15 x + 186 = 0

x = \frac{5}{2} + i \frac{223}{2}, x = \frac{5}{2} - i \frac{223}{2}

Solution steps

3 x^{2} - 15 x + 186 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 3 \cdot 186}{2 \cdot 3}

Simplify

(- 15)^{2} - 4 \cdot 3 \cdot 186 : 3223 i

x_{1, 2} = \frac{- ( - 15 ) \pm 3 223 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 3 223 i}{2 \cdot 3}, x_{2} = \frac{- ( - 15 ) - 3 223 i}{2 \cdot 3}

x = \frac{- ( - 15 ) + 3 223 i}{2 \cdot 3} : \frac{5}{2} + i \frac{223}{2}

x = \frac{- ( - 15 ) - 3 223 i}{2 \cdot 3} : \frac{5}{2} - i \frac{223}{2}

The solutions to the quadratic equation are:

x = \frac{5}{2} + i \frac{223}{2}, x = \frac{5}{2} - i \frac{223}{2}

2 X^{2} = 0

3 (x^{2} + 1) = 5 (1 - x)

121 = x^{2}

(x - 2)^{2} + 2 = x

- 2 x^{2} - 8 x - 6 = 0

What are the solutions to the equation 3x^2-15x+186=0 ?
The solutions to the equation 3x^2-15x+186=0 are x= 5/2+i(sqrt(223))/2 ,x= 5/2-i(sqrt(223))/2
Find the zeros of 3x^2-15x+186=0
The zeros of 3x^2-15x+186=0 are x= 5/2+i(sqrt(223))/2 ,x= 5/2-i(sqrt(223))/2