What are the solutions to the equation -2x^2-8x-6=0 ?

The solutions to the equation -2x^2-8x-6=0 are x=-3,x=-1

Find the zeros of -2x^2-8x-6=0

The zeros of -2x^2-8x-6=0 are x=-3,x=-1

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- 2 x^{2} - 8 x - 6 = 0

x = - 3, x = - 1

Solution steps

- 2 x^{2} - 8 x - 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 ( - 2 ) ( - 6 )}{2 ( - 2 )}

(- 8)^{2} - 4 (- 2) (- 6) = 4

x_{1, 2} = \frac{- ( - 8 ) \pm 4}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 4}{2 ( - 2 )}, x_{2} = \frac{- ( - 8 ) - 4}{2 ( - 2 )}

x = \frac{- ( - 8 ) + 4}{2 ( - 2 )} : - 3

x = \frac{- ( - 8 ) - 4}{2 ( - 2 )} : - 1

The solutions to the quadratic equation are:

x = - 3, x = - 1

- m^{2} + 14 m - 11 = 6 m - 2

3 x (x - 6) - 42 = 6

10 x + 4 = 6 x^{2}

- x + x^{2} = 12

(- \frac{1}{2}) x^{2} = - 3 x + 17

What are the solutions to the equation -2x^2-8x-6=0 ?
The solutions to the equation -2x^2-8x-6=0 are x=-3,x=-1
Find the zeros of -2x^2-8x-6=0
The zeros of -2x^2-8x-6=0 are x=-3,x=-1