What are the solutions to the equation -m^2+14m-11=6m-2 ?

The solutions to the equation -m^2+14m-11=6m-2 are m=4-sqrt(7),m=4+sqrt(7)

Find the zeros of -m^2+14m-11=6m-2

The zeros of -m^2+14m-11=6m-2 are m=4-sqrt(7),m=4+sqrt(7)

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- m^{2} + 14 m - 11 = 6 m - 2

m = 4 - 7, m = 4 + 7

Decimal Notation

m = 1.35424 \dots, m = 6.64575 \dots

Solution steps

- m^{2} + 14 m - 11 = 6 m - 2

Move

2

to the left side

- m^{2} + 14 m - 9 = 6 m

Move

6 m

to the left side

- m^{2} + 8 m - 9 = 0

Solve with the quadratic formula

m_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 ( - 1 ) ( - 9 )}{2 ( - 1 )}

8^{2} - 4 (- 1) (- 9) = 27

m_{1, 2} = \frac{- 8 \pm 2 7}{2 ( - 1 )}

Separate the solutions

m_{1} = \frac{- 8 + 2 7}{2 ( - 1 )}, m_{2} = \frac{- 8 - 2 7}{2 ( - 1 )}

m = \frac{- 8 + 2 7}{2 ( - 1 )} : 4 - 7

m = \frac{- 8 - 2 7}{2 ( - 1 )} : 4 + 7

The solutions to the quadratic equation are:

m = 4 - 7, m = 4 + 7

3 x (x - 6) - 42 = 6

10 x + 4 = 6 x^{2}

- x + x^{2} = 12

(- \frac{1}{2}) x^{2} = - 3 x + 17

5 x^{2} - x - 9 = 0

What are the solutions to the equation -m^2+14m-11=6m-2 ?
The solutions to the equation -m^2+14m-11=6m-2 are m=4-sqrt(7),m=4+sqrt(7)
Find the zeros of -m^2+14m-11=6m-2
The zeros of -m^2+14m-11=6m-2 are m=4-sqrt(7),m=4+sqrt(7)