What are the solutions to the equation 5x^2-x-9=0 ?

The solutions to the equation 5x^2-x-9=0 are x=(1+sqrt(181))/(10),x=(1-sqrt(181))/(10)

Find the zeros of 5x^2-x-9=0

The zeros of 5x^2-x-9=0 are x=(1+sqrt(181))/(10),x=(1-sqrt(181))/(10)

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5 x^{2} - x - 9 = 0

x = \frac{1 + 181}{10}, x = \frac{1 - 181}{10}

Decimal Notation

x = 1.44536 \dots, x = - 1.24536 \dots

Solution steps

5 x^{2} - x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 5 ( - 9 )}{2 \cdot 5}

(- 1)^{2} - 4 \cdot 5 (- 9) = 181

x_{1, 2} = \frac{- ( - 1 ) \pm 181}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 181}{2 \cdot 5}, x_{2} = \frac{- ( - 1 ) - 181}{2 \cdot 5}

x = \frac{- ( - 1 ) + 181}{2 \cdot 5} : \frac{1 + 181}{10}

x = \frac{- ( - 1 ) - 181}{2 \cdot 5} : \frac{1 - 181}{10}

The solutions to the quadratic equation are:

x = \frac{1 + 181}{10}, x = \frac{1 - 181}{10}

13 x^{2} - 26 x - 182 = 13

2^{2} + 3^{2} = r^{2}

- 9 e^{2} + 5 e - 9 = 0

x^{2} + x + 0.25 = 0

7 x^{2} + 34 = 5 x^{2} + 20 + 14

What are the solutions to the equation 5x^2-x-9=0 ?
The solutions to the equation 5x^2-x-9=0 are x=(1+sqrt(181))/(10),x=(1-sqrt(181))/(10)
Find the zeros of 5x^2-x-9=0
The zeros of 5x^2-x-9=0 are x=(1+sqrt(181))/(10),x=(1-sqrt(181))/(10)