What are the solutions to the equation 13x^2-26x-182=13 ?

The solutions to the equation 13x^2-26x-182=13 are x=5,x=-3

Find the zeros of 13x^2-26x-182=13

The zeros of 13x^2-26x-182=13 are x=5,x=-3

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13 x^{2} - 26 x - 182 = 13

x = 5, x = - 3

Solution steps

13 x^{2} - 26 x - 182 = 13

Move

13

to the left side

13 x^{2} - 26 x - 195 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 26 ) \pm ( - 26 ) ^{2} - 4 \cdot 13 ( - 195 )}{2 \cdot 13}

(- 26)^{2} - 4 \cdot 13 (- 195) = 104

x_{1, 2} = \frac{- ( - 26 ) \pm 104}{2 \cdot 13}

Separate the solutions

x_{1} = \frac{- ( - 26 ) + 104}{2 \cdot 13}, x_{2} = \frac{- ( - 26 ) - 104}{2 \cdot 13}

x = \frac{- ( - 26 ) + 104}{2 \cdot 13} : 5

x = \frac{- ( - 26 ) - 104}{2 \cdot 13} : - 3

The solutions to the quadratic equation are:

x = 5, x = - 3

2^{2} + 3^{2} = r^{2}

- 9 e^{2} + 5 e - 9 = 0

x^{2} + x + 0.25 = 0

7 x^{2} + 34 = 5 x^{2} + 20 + 14

0 = - x^{2} + 4 x - 4

What are the solutions to the equation 13x^2-26x-182=13 ?
The solutions to the equation 13x^2-26x-182=13 are x=5,x=-3
Find the zeros of 13x^2-26x-182=13
The zeros of 13x^2-26x-182=13 are x=5,x=-3