What are the solutions to the equation (2D-1)^2=0 ?

The solutions to the equation (2D-1)^2=0 are D= 1/2

Find the zeros of (2D-1)^2=0

The zeros of (2D-1)^2=0 are D= 1/2

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(2 D - 1)^{2} = 0

D = \frac{1}{2}

Decimal Notation

D = 0.5

Solution steps

(2 D - 1)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

Solve

2 D - 1 = 0 : D = \frac{1}{2}

The solution to the quadratic equation is:

D = \frac{1}{2}

14 = x^{2} + 5 x

(x + 9)^{2} = x^{2} + (x + 1)^{2}

4 x^{2} - 3 = x

(m - 2)^{2} = (m - 4)^{2} + (m - 3)^{2}

x^{2} - \frac{3}{4} = 0

What are the solutions to the equation (2D-1)^2=0 ?
The solutions to the equation (2D-1)^2=0 are D= 1/2
Find the zeros of (2D-1)^2=0
The zeros of (2D-1)^2=0 are D= 1/2