What are the solutions to the equation 4x^2-3=x ?

The solutions to the equation 4x^2-3=x are x=1,x=-3/4

Find the zeros of 4x^2-3=x

The zeros of 4x^2-3=x are x=1,x=-3/4

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4 x^{2} - 3 = x

x = 1, x = - \frac{3}{4}

Decimal Notation

x = 1, x = - 0.75

Solution steps

4 x^{2} - 3 = x

Move

x

to the left side

4 x^{2} - 3 - x = 0

Write in the standard form

a x^{2} + b x + c = 0

4 x^{2} - x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 4 ( - 3 )}{2 \cdot 4}

(- 1)^{2} - 4 \cdot 4 (- 3) = 7

x_{1, 2} = \frac{- ( - 1 ) \pm 7}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 7}{2 \cdot 4}, x_{2} = \frac{- ( - 1 ) - 7}{2 \cdot 4}

x = \frac{- ( - 1 ) + 7}{2 \cdot 4} : 1

x = \frac{- ( - 1 ) - 7}{2 \cdot 4} : - \frac{3}{4}

The solutions to the quadratic equation are:

x = 1, x = - \frac{3}{4}

(m - 2)^{2} = (m - 4)^{2} + (m - 3)^{2}

x^{2} - \frac{3}{4} = 0

- 2 x^{2} + 4 x + 4 = 0

x, 5 x^{2} - 9 y^{2} + 10 x + 36 y - 31 = 0

3 y^{2} - 6 y

What are the solutions to the equation 4x^2-3=x ?
The solutions to the equation 4x^2-3=x are x=1,x=-3/4
Find the zeros of 4x^2-3=x
The zeros of 4x^2-3=x are x=1,x=-3/4