What are the solutions to the equation -2x^2+4x+4=0 ?

The solutions to the equation -2x^2+4x+4=0 are x=1-sqrt(3),x=1+sqrt(3)

Find the zeros of -2x^2+4x+4=0

The zeros of -2x^2+4x+4=0 are x=1-sqrt(3),x=1+sqrt(3)

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- 2 x^{2} + 4 x + 4 = 0

x = 1 - 3, x = 1 + 3

Decimal Notation

x = - 0.73205 \dots, x = 2.73205 \dots

Solution steps

- 2 x^{2} + 4 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 2 ) \cdot 4}{2 ( - 2 )}

4^{2} - 4 (- 2) \cdot 4 = 43

x_{1, 2} = \frac{- 4 \pm 4 3}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- 4 + 4 3}{2 ( - 2 )}, x_{2} = \frac{- 4 - 4 3}{2 ( - 2 )}

x = \frac{- 4 + 4 3}{2 ( - 2 )} : 1 - 3

x = \frac{- 4 - 4 3}{2 ( - 2 )} : 1 + 3

The solutions to the quadratic equation are:

x = 1 - 3, x = 1 + 3

x, 5 x^{2} - 9 y^{2} + 10 x + 36 y - 31 = 0

3 y^{2} - 6 y

4 a^{2} + 4 = 72

(3 x + 4)^{2} = 27

2 x^{2} + 4 = 2 x

What are the solutions to the equation -2x^2+4x+4=0 ?
The solutions to the equation -2x^2+4x+4=0 are x=1-sqrt(3),x=1+sqrt(3)
Find the zeros of -2x^2+4x+4=0
The zeros of -2x^2+4x+4=0 are x=1-sqrt(3),x=1+sqrt(3)