What are the solutions to the equation 4a^2+4=72 ?

The solutions to the equation 4a^2+4=72 are a=sqrt(17),a=-sqrt(17)

Find the zeros of 4a^2+4=72

The zeros of 4a^2+4=72 are a=sqrt(17),a=-sqrt(17)

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4 a^{2} + 4 = 72

a = 17, a = - 17

Decimal Notation

a = 4.12310 \dots, a = - 4.12310 \dots

Solution steps

4 a^{2} + 4 = 72

Move

4

to the right side

4 a^{2} = 68

Divide both sides by

4

a^{2} = 17

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = 17, a = - 17

(3 x + 4)^{2} = 27

2 x^{2} + 4 = 2 x

2 y^{2} + 8 = 0

x^{2} + 50 x = 0

(2 x - 3)^{2} - (x + 5)^{2} = 23

What are the solutions to the equation 4a^2+4=72 ?
The solutions to the equation 4a^2+4=72 are a=sqrt(17),a=-sqrt(17)
Find the zeros of 4a^2+4=72
The zeros of 4a^2+4=72 are a=sqrt(17),a=-sqrt(17)