What are the solutions to the equation 2y^2+8=0 ?

The solutions to the equation 2y^2+8=0 are y=2i,y=-2i

Find the zeros of 2y^2+8=0

The zeros of 2y^2+8=0 are y=2i,y=-2i

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2 y^{2} + 8 = 0

y = 2 i, y = - 2 i

Solution steps

2 y^{2} + 8 = 0

Move

8

to the right side

2 y^{2} = - 8

Divide both sides by

2

y^{2} = - 4

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = - 4, y = - - 4

- 4 = 2 i

- - 4 = - 2 i

y = 2 i, y = - 2 i

x^{2} + 50 x = 0

(2 x - 3)^{2} - (x + 5)^{2} = 23

x, 0 = x^{2} - 2 x - 3

(2 a)^{2} + a^{2} + (a - 1)^{2} = (a + 1)^{2} + (a - 2)^{2}

7 x^{2} + 30 x - 25 = 0

What are the solutions to the equation 2y^2+8=0 ?
The solutions to the equation 2y^2+8=0 are y=2i,y=-2i
Find the zeros of 2y^2+8=0
The zeros of 2y^2+8=0 are y=2i,y=-2i