What are the solutions to the equation -8x^2+x-2=-18 ?

The solutions to the equation -8x^2+x-2=-18 are x=-(-1+3sqrt(57))/(16),x=(1+3sqrt(57))/(16)

Find the zeros of -8x^2+x-2=-18

The zeros of -8x^2+x-2=-18 are x=-(-1+3sqrt(57))/(16),x=(1+3sqrt(57))/(16)

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- 8 x^{2} + x - 2 = - 18

x = - \frac{- 1 + 3 57}{16}, x = \frac{1 + 3 57}{16}

Decimal Notation

x = - 1.35309 \dots, x = 1.47809 \dots

Solution steps

- 8 x^{2} + x - 2 = - 18

Move

18

to the left side

- 8 x^{2} + x + 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 ( - 8 ) \cdot 16}{2 ( - 8 )}

1^{2} - 4 (- 8) \cdot 16 = 357

x_{1, 2} = \frac{- 1 \pm 3 57}{2 ( - 8 )}

Separate the solutions

x_{1} = \frac{- 1 + 3 57}{2 ( - 8 )}, x_{2} = \frac{- 1 - 3 57}{2 ( - 8 )}

x = \frac{- 1 + 3 57}{2 ( - 8 )} : - \frac{- 1 + 3 57}{16}

x = \frac{- 1 - 3 57}{2 ( - 8 )} : \frac{1 + 3 57}{16}

The solutions to the quadratic equation are:

x = - \frac{- 1 + 3 57}{16}, x = \frac{1 + 3 57}{16}

x^{2} + \frac{29}{4} x + \frac{7}{4} = 0

y^{2} - 2 = 6 - y^{2}

x^{2} - 12 x + 36 = 0

25 - x^{3} = (4 - x)^{3}

0 = x^{2} - 6 x - 8

What are the solutions to the equation -8x^2+x-2=-18 ?
The solutions to the equation -8x^2+x-2=-18 are x=-(-1+3sqrt(57))/(16),x=(1+3sqrt(57))/(16)
Find the zeros of -8x^2+x-2=-18
The zeros of -8x^2+x-2=-18 are x=-(-1+3sqrt(57))/(16),x=(1+3sqrt(57))/(16)