What are the solutions to the equation factor x^2-12x+36=0 ?

The solutions to the equation factor x^2-12x+36=0 are x=6

Find the zeros of factor x^2-12x+36=0

The zeros of factor x^2-12x+36=0 are x=6

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x^{2} - 12 x + 36 = 0

x = 6

Solution steps

x^{2} - 12 x + 36 = 0

Factor

x^{2} - 12 x + 36 : (x - 6)^{2}

(x - 6)^{2} = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 6 = 0

Solve

x - 6 = 0 : x = 6

The solution to the quadratic equation is:

x = 6

25 - x^{3} = (4 - x)^{3}

0 = x^{2} - 6 x - 8

- 2 x^{2} - 1 = 0

X^{2} - 4 X + 3 = 0

(x + 3)^{2} + 8 = 0

What are the solutions to the equation factor x^2-12x+36=0 ?
The solutions to the equation factor x^2-12x+36=0 are x=6
Find the zeros of factor x^2-12x+36=0
The zeros of factor x^2-12x+36=0 are x=6