What are the solutions to the equation -2x^2-1=0 ?

The solutions to the equation -2x^2-1=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i

Find the zeros of -2x^2-1=0

The zeros of -2x^2-1=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i

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- 2 x^{2} - 1 = 0

x = \frac{1}{2} i, x = - \frac{1}{2} i

Solution steps

- 2 x^{2} - 1 = 0

Move

1

to the right side

- 2 x^{2} = 1

Divide both sides by

- 2

x^{2} = - \frac{1}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{1}{2}, x = - - \frac{1}{2}

- \frac{1}{2} = \frac{1}{2} i

- - \frac{1}{2} = - \frac{1}{2} i

x = \frac{1}{2} i, x = - \frac{1}{2} i

X^{2} - 4 X + 3 = 0

(x + 3)^{2} + 8 = 0

- x^{2} + 6 x - 10

k^{2} = 2 k

k^{2} = 64

What are the solutions to the equation -2x^2-1=0 ?
The solutions to the equation -2x^2-1=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i
Find the zeros of -2x^2-1=0
The zeros of -2x^2-1=0 are x= 1/(sqrt(2))i,x=-1/(sqrt(2))i