What are the solutions to the equation k^2=2k ?

The solutions to the equation k^2=2k are k=2,k=0

Find the zeros of k^2=2k

The zeros of k^2=2k are k=2,k=0

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k^{2} = 2 k

k = 2, k = 0

Solution steps

k^{2} = 2 k

Move

2 k

to the left side

k^{2} - 2 k = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot 0 = 2

k_{1, 2} = \frac{- ( - 2 ) \pm 2}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 2 ) + 2}{2 \cdot 1}, k_{2} = \frac{- ( - 2 ) - 2}{2 \cdot 1}

k = \frac{- ( - 2 ) + 2}{2 \cdot 1} : 2

k = \frac{- ( - 2 ) - 2}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

k = 2, k = 0

k^{2} = 64

x^{2} - x = 90

X^{2} + 2 X + 1 = 3 X - 10

(x + 4) 2 = 2 x (5 x - 1) - 7 (x - 2)

x^{2} - 6 x + 8 = 0

What are the solutions to the equation k^2=2k ?
The solutions to the equation k^2=2k are k=2,k=0
Find the zeros of k^2=2k
The zeros of k^2=2k are k=2,k=0