What are the solutions to the equation x^2-x=90 ?

The solutions to the equation x^2-x=90 are x=10,x=-9

Find the zeros of x^2-x=90

The zeros of x^2-x=90 are x=10,x=-9

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x^{2} - x = 90

x = 10, x = - 9

Solution steps

x^{2} - x = 90

Move

90

to the left side

x^{2} - x - 90 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 90 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 90) = 19

x_{1, 2} = \frac{- ( - 1 ) \pm 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 19}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 19}{2 \cdot 1}

x = \frac{- ( - 1 ) + 19}{2 \cdot 1} : 10

x = \frac{- ( - 1 ) - 19}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 10, x = - 9

X^{2} + 2 X + 1 = 3 X - 10

(x + 4) 2 = 2 x (5 x - 1) - 7 (x - 2)

x^{2} - 6 x + 8 = 0

0 = x^{2} - 6 x + 4

14 x^{2} + 73 x - 22 = 0

What are the solutions to the equation x^2-x=90 ?
The solutions to the equation x^2-x=90 are x=10,x=-9
Find the zeros of x^2-x=90
The zeros of x^2-x=90 are x=10,x=-9