What are the solutions to the equation x^2=(x-1)^2+(x-2)^2 ?

The solutions to the equation x^2=(x-1)^2+(x-2)^2 are x=5,x=1

Find the zeros of x^2=(x-1)^2+(x-2)^2

The zeros of x^2=(x-1)^2+(x-2)^2 are x=5,x=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} = (x - 1)^{2} + (x - 2)^{2}

x = 5, x = 1

Solution steps

x^{2} = (x - 1)^{2} + (x - 2)^{2}

Expand

(x - 1)^{2} + (x - 2)^{2} : 2 x^{2} - 6 x + 5

x^{2} = 2 x^{2} - 6 x + 5

Switch sides

2 x^{2} - 6 x + 5 = x^{2}

Move

x^{2}

to the left side

x^{2} - 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 5 = 4

x_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 4}{2 \cdot 1}

x = \frac{- ( - 6 ) + 4}{2 \cdot 1} : 5

x = \frac{- ( - 6 ) - 4}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 5, x = 1

10 x = - 25 - x^{2}

x^{2} + 7 x + 30 = 18

6 x^{2} + 12 x + 14 = 7 x^{2} - 5

2 x^{2} + 5 = 6 x

5 x^{2} + 7 x - 24 = 0

What are the solutions to the equation x^2=(x-1)^2+(x-2)^2 ?
The solutions to the equation x^2=(x-1)^2+(x-2)^2 are x=5,x=1
Find the zeros of x^2=(x-1)^2+(x-2)^2
The zeros of x^2=(x-1)^2+(x-2)^2 are x=5,x=1