What are the solutions to the equation 6x^2+12x+14=7x^2-5 ?

The solutions to the equation 6x^2+12x+14=7x^2-5 are x=6-sqrt(55),x=6+sqrt(55)

Find the zeros of 6x^2+12x+14=7x^2-5

The zeros of 6x^2+12x+14=7x^2-5 are x=6-sqrt(55),x=6+sqrt(55)

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6 x^{2} + 12 x + 14 = 7 x^{2} - 5

x = 6 - 55, x = 6 + 55

Decimal Notation

x = - 1.41619 \dots, x = 13.41619 \dots

Solution steps

6 x^{2} + 12 x + 14 = 7 x^{2} - 5

Move

5

to the left side

6 x^{2} + 12 x + 19 = 7 x^{2}

Move

7 x^{2}

to the left side

- x^{2} + 12 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 ( - 1 ) \cdot 19}{2 ( - 1 )}

1 2^{2} - 4 (- 1) \cdot 19 = 255

x_{1, 2} = \frac{- 12 \pm 2 55}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 12 + 2 55}{2 ( - 1 )}, x_{2} = \frac{- 12 - 2 55}{2 ( - 1 )}

x = \frac{- 12 + 2 55}{2 ( - 1 )} : 6 - 55

x = \frac{- 12 - 2 55}{2 ( - 1 )} : 6 + 55

The solutions to the quadratic equation are:

x = 6 - 55, x = 6 + 55

2 x^{2} + 5 = 6 x

5 x^{2} + 7 x - 24 = 0

x (x + 1) = 42

- 2 x^{2} + 1000 x = 0

4 x^{2} + 9 x - 63 = 0

What are the solutions to the equation 6x^2+12x+14=7x^2-5 ?
The solutions to the equation 6x^2+12x+14=7x^2-5 are x=6-sqrt(55),x=6+sqrt(55)
Find the zeros of 6x^2+12x+14=7x^2-5
The zeros of 6x^2+12x+14=7x^2-5 are x=6-sqrt(55),x=6+sqrt(55)