What are the solutions to the equation 4x^2+9x-63=0 ?

The solutions to the equation 4x^2+9x-63=0 are x=3,x=-21/4

Find the zeros of 4x^2+9x-63=0

The zeros of 4x^2+9x-63=0 are x=3,x=-21/4

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4 x^{2} + 9 x - 63 = 0

x = 3, x = - \frac{21}{4}

Decimal Notation

x = 3, x = - 5.25

Solution steps

4 x^{2} + 9 x - 63 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 4 ( - 63 )}{2 \cdot 4}

9^{2} - 4 \cdot 4 (- 63) = 33

x_{1, 2} = \frac{- 9 \pm 33}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 9 + 33}{2 \cdot 4}, x_{2} = \frac{- 9 - 33}{2 \cdot 4}

x = \frac{- 9 + 33}{2 \cdot 4} : 3

x = \frac{- 9 - 33}{2 \cdot 4} : - \frac{21}{4}

The solutions to the quadratic equation are:

x = 3, x = - \frac{21}{4}

x^{2} + 76 = 400

x^{2} - 14 x + 47 = 8

5 x^{2} + 14 x - 48 = 0

7 x^{2} + 8 x

x, x^{2} - y^{2} + 2 x y = c

What are the solutions to the equation 4x^2+9x-63=0 ?
The solutions to the equation 4x^2+9x-63=0 are x=3,x=-21/4
Find the zeros of 4x^2+9x-63=0
The zeros of 4x^2+9x-63=0 are x=3,x=-21/4