What are the solutions to the equation x^2-14x+47=8 ?

The solutions to the equation x^2-14x+47=8 are x=7+sqrt(10),x=7-sqrt(10)

Find the zeros of x^2-14x+47=8

The zeros of x^2-14x+47=8 are x=7+sqrt(10),x=7-sqrt(10)

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x^{2} - 14 x + 47 = 8

x = 7 + 10, x = 7 - 10

Decimal Notation

x = 10.16227 \dots, x = 3.83772 \dots

Solution steps

x^{2} - 14 x + 47 = 8

Move

8

to the left side

x^{2} - 14 x + 39 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 14 ) \pm ( - 14 ) ^{2} - 4 \cdot 1 \cdot 39}{2 \cdot 1}

(- 14)^{2} - 4 \cdot 1 \cdot 39 = 210

x_{1, 2} = \frac{- ( - 14 ) \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 14 ) + 2 10}{2 \cdot 1}, x_{2} = \frac{- ( - 14 ) - 2 10}{2 \cdot 1}

x = \frac{- ( - 14 ) + 2 10}{2 \cdot 1} : 7 + 10

x = \frac{- ( - 14 ) - 2 10}{2 \cdot 1} : 7 - 10

The solutions to the quadratic equation are:

x = 7 + 10, x = 7 - 10

5 x^{2} + 14 x - 48 = 0

7 x^{2} + 8 x

x, x^{2} - y^{2} + 2 x y = c

(x - 2)^{2} - 3 = 1

4 x^{2} + 8 x - 252 = 0

What are the solutions to the equation x^2-14x+47=8 ?
The solutions to the equation x^2-14x+47=8 are x=7+sqrt(10),x=7-sqrt(10)
Find the zeros of x^2-14x+47=8
The zeros of x^2-14x+47=8 are x=7+sqrt(10),x=7-sqrt(10)