What are the solutions to the equation 1/3 r^2+3r+6=0 ?

The solutions to the equation 1/3 r^2+3r+6=0 are r=-3,r=-6

Find the zeros of 1/3 r^2+3r+6=0

The zeros of 1/3 r^2+3r+6=0 are r=-3,r=-6

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\frac{1}{3} r^{2} + 3 r + 6 = 0

r = - 3, r = - 6

Solution steps

\frac{1}{3} r^{2} + 3 r + 6 = 0

Multiply both sides by

3

r^{2} + 9 r + 18 = 0

Solve with the quadratic formula

r_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot 18}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot 18 = 3

r_{1, 2} = \frac{- 9 \pm 3}{2 \cdot 1}

Separate the solutions

r_{1} = \frac{- 9 + 3}{2 \cdot 1}, r_{2} = \frac{- 9 - 3}{2 \cdot 1}

r = \frac{- 9 + 3}{2 \cdot 1} : - 3

r = \frac{- 9 - 3}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

r = - 3, r = - 6

6 x^{2} = 2 x + 1

- 13 = x^{2} - 4 x

160 - 104 x + 12 x^{2} = 0

\frac{1}{2} x^{2} + \frac{1}{4} x - \frac{1}{6} = 0

n^{2} - 16 = 0

What are the solutions to the equation 1/3 r^2+3r+6=0 ?
The solutions to the equation 1/3 r^2+3r+6=0 are r=-3,r=-6
Find the zeros of 1/3 r^2+3r+6=0
The zeros of 1/3 r^2+3r+6=0 are r=-3,r=-6