What are the solutions to the equation x^2=1-6x ?

The solutions to the equation x^2=1-6x are x=-3+sqrt(10),x=-3-sqrt(10)

Find the zeros of x^2=1-6x

The zeros of x^2=1-6x are x=-3+sqrt(10),x=-3-sqrt(10)

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x^{2} = 1 - 6 x

x = - 3 + 10, x = - 3 - 10

Decimal Notation

x = 0.16227 \dots, x = - 6.16227 \dots

Solution steps

x^{2} = 1 - 6 x

Move

6 x

to the left side

x^{2} + 6 x = 1

Move

1

to the left side

x^{2} + 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 1) = 210

x_{1, 2} = \frac{- 6 \pm 2 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 2 10}{2 \cdot 1}, x_{2} = \frac{- 6 - 2 10}{2 \cdot 1}

x = \frac{- 6 + 2 10}{2 \cdot 1} : - 3 + 10

x = \frac{- 6 - 2 10}{2 \cdot 1} : - 3 - 10

The solutions to the quadratic equation are:

x = - 3 + 10, x = - 3 - 10

4 x^{2} - 24 x + 16 = 0

3 x^{2} - 6 x - 36 = 0

(x - 6)^{2} = 20

(x - 6)^{2} = 12

(x - 6)^{2} = - 4

What are the solutions to the equation x^2=1-6x ?
The solutions to the equation x^2=1-6x are x=-3+sqrt(10),x=-3-sqrt(10)
Find the zeros of x^2=1-6x
The zeros of x^2=1-6x are x=-3+sqrt(10),x=-3-sqrt(10)