What are the solutions to the equation x^2+10x+20=-5 ?

The solutions to the equation x^2+10x+20=-5 are x=-5

Find the zeros of x^2+10x+20=-5

The zeros of x^2+10x+20=-5 are x=-5

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x^{2} + 10 x + 20 = - 5

x = - 5

Solution steps

x^{2} + 10 x + 20 = - 5

Move

5

to the left side

x^{2} + 10 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 10 \pm 1 0 ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

1 0^{2} - 4 \cdot 1 \cdot 25 = 0

x_{1, 2} = \frac{- 10 \pm 0}{2 \cdot 1}

x = \frac{- 10}{2 \cdot 1}

\frac{- 10}{2 \cdot 1} = - 5

x = - 5

The solution to the quadratic equation is:

x = - 5

4 x - 7 x = 1 - 7 x^{2} + 5 - 3 x^{2} + 7 x + 8 x^{2} - 6

k, y^{n} + k^{2} y = 0

m^{2} + 8 m = 16

(x - 2)^{2} - 2 (x - 2) - 15 = 0

(5 c + 1)^{2} = - 27

What are the solutions to the equation x^2+10x+20=-5 ?
The solutions to the equation x^2+10x+20=-5 are x=-5
Find the zeros of x^2+10x+20=-5
The zeros of x^2+10x+20=-5 are x=-5