What are the solutions to the equation -4x^2+3x-5=0 ?

The solutions to the equation -4x^2+3x-5=0 are x= 3/8-i(sqrt(71))/8 ,x= 3/8+i(sqrt(71))/8

Find the zeros of -4x^2+3x-5=0

The zeros of -4x^2+3x-5=0 are x= 3/8-i(sqrt(71))/8 ,x= 3/8+i(sqrt(71))/8

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- 4 x^{2} + 3 x - 5 = 0

x = \frac{3}{8} - i \frac{71}{8}, x = \frac{3}{8} + i \frac{71}{8}

Solution steps

- 4 x^{2} + 3 x - 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 3 \pm 3 ^{2} - 4 ( - 4 ) ( - 5 )}{2 ( - 4 )}

Simplify

3^{2} - 4 (- 4) (- 5) : 71 i

x_{1, 2} = \frac{- 3 \pm 71 i}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 3 + 71 i}{2 ( - 4 )}, x_{2} = \frac{- 3 - 71 i}{2 ( - 4 )}

x = \frac{- 3 + 71 i}{2 ( - 4 )} : \frac{3}{8} - i \frac{71}{8}

x = \frac{- 3 - 71 i}{2 ( - 4 )} : \frac{3}{8} + i \frac{71}{8}

The solutions to the quadratic equation are:

x = \frac{3}{8} - i \frac{71}{8}, x = \frac{3}{8} + i \frac{71}{8}

4 b^{2} + 8 b + 7 = 0

x^{2} + 2 x = 8

- 2 x^{2} - 16 x - 31

2 x^{2} = 18 x - 36

a^{2} - 6 a = - 8

What are the solutions to the equation -4x^2+3x-5=0 ?
The solutions to the equation -4x^2+3x-5=0 are x= 3/8-i(sqrt(71))/8 ,x= 3/8+i(sqrt(71))/8
Find the zeros of -4x^2+3x-5=0
The zeros of -4x^2+3x-5=0 are x= 3/8-i(sqrt(71))/8 ,x= 3/8+i(sqrt(71))/8