What are the solutions to the equation 3x^2-3x=9 ?

The solutions to the equation 3x^2-3x=9 are x=(1+sqrt(13))/2 ,x=(1-sqrt(13))/2

Find the zeros of 3x^2-3x=9

The zeros of 3x^2-3x=9 are x=(1+sqrt(13))/2 ,x=(1-sqrt(13))/2

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3 x^{2} - 3 x = 9

x = \frac{1 + 13}{2}, x = \frac{1 - 13}{2}

Decimal Notation

x = 2.30277 \dots, x = - 1.30277 \dots

Solution steps

3 x^{2} - 3 x = 9

Move

9

to the left side

3 x^{2} - 3 x - 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 3 ( - 9 )}{2 \cdot 3}

(- 3)^{2} - 4 \cdot 3 (- 9) = 313

x_{1, 2} = \frac{- ( - 3 ) \pm 3 13}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 3 13}{2 \cdot 3}, x_{2} = \frac{- ( - 3 ) - 3 13}{2 \cdot 3}

x = \frac{- ( - 3 ) + 3 13}{2 \cdot 3} : \frac{1 + 13}{2}

x = \frac{- ( - 3 ) - 3 13}{2 \cdot 3} : \frac{1 - 13}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 13}{2}, x = \frac{1 - 13}{2}

2 p^{2} + 8 p + (k + 1) = 0

x^{2} + 2 x - 3 = 0

s^{2} + 2 s + 2 = 0

\frac{x}{3} = x^{2}

(2 x - 9) (x + 2) = 24

What are the solutions to the equation 3x^2-3x=9 ?
The solutions to the equation 3x^2-3x=9 are x=(1+sqrt(13))/2 ,x=(1-sqrt(13))/2
Find the zeros of 3x^2-3x=9
The zeros of 3x^2-3x=9 are x=(1+sqrt(13))/2 ,x=(1-sqrt(13))/2