What are the solutions to the equation -9x^2+40x+84=0 ?

The solutions to the equation -9x^2+40x+84=0 are x=-14/9 ,x=6

Find the zeros of -9x^2+40x+84=0

The zeros of -9x^2+40x+84=0 are x=-14/9 ,x=6

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- 9 x^{2} + 40 x + 84 = 0

x = - \frac{14}{9}, x = 6

Decimal Notation

x = - 1.55555 \dots, x = 6

Solution steps

- 9 x^{2} + 40 x + 84 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 40 \pm 4 0 ^{2} - 4 ( - 9 ) \cdot 84}{2 ( - 9 )}

4 0^{2} - 4 (- 9) \cdot 84 = 68

x_{1, 2} = \frac{- 40 \pm 68}{2 ( - 9 )}

Separate the solutions

x_{1} = \frac{- 40 + 68}{2 ( - 9 )}, x_{2} = \frac{- 40 - 68}{2 ( - 9 )}

x = \frac{- 40 + 68}{2 ( - 9 )} : - \frac{14}{9}

x = \frac{- 40 - 68}{2 ( - 9 )} : 6

The solutions to the quadratic equation are:

x = - \frac{14}{9}, x = 6

x^{2} - 12 x + 100 = 80

x^{2} = 3 + 2 x

x^{2} + 0.1 x + 0.0018 = 0

m x^{2} - 2 (m - 1) x + 3 m - 1 = 0

0 = 12 x^{2} - 204 x + 594

What are the solutions to the equation -9x^2+40x+84=0 ?
The solutions to the equation -9x^2+40x+84=0 are x=-14/9 ,x=6
Find the zeros of -9x^2+40x+84=0
The zeros of -9x^2+40x+84=0 are x=-14/9 ,x=6