What are the solutions to the equation quadraticformula 9x^2-12x+4=0 ?

The solutions to the equation quadraticformula 9x^2-12x+4=0 are x= 2/3

Find the zeros of quadraticformula 9x^2-12x+4=0

The zeros of quadraticformula 9x^2-12x+4=0 are x= 2/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

9 x^{2} - 12 x + 4 = 0

x = \frac{2}{3}

Decimal

x = 0.66666 \dots

Solution steps

9 x^{2} - 12 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

(- 12)^{2} - 4 \cdot 9 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 9}

x = \frac{- ( - 12 )}{2 \cdot 9}

\frac{- ( - 12 )}{2 \cdot 9} = \frac{2}{3}

x = \frac{2}{3}

The solution to the quadratic equation is:

x = \frac{2}{3}

x^{2} + 6 x = 7

x^{2} - 13 x - 72 = - 7 x

x, (m^{2} x) (m x - 1) = m^{2} x + 5

n^{2} - 6 n - 16 = 0

x^{2} = 3^{2} + 2^{2}

What are the solutions to the equation quadraticformula 9x^2-12x+4=0 ?
The solutions to the equation quadraticformula 9x^2-12x+4=0 are x= 2/3
Find the zeros of quadraticformula 9x^2-12x+4=0
The zeros of quadraticformula 9x^2-12x+4=0 are x= 2/3