What are the solutions to the equation completesquare x^2+2x-12=0 ?

The solutions to the equation completesquare x^2+2x-12=0 are x=sqrt(13)-1,x=-sqrt(13)-1

Find the zeros of completesquare x^2+2x-12=0

The zeros of completesquare x^2+2x-12=0 are x=sqrt(13)-1,x=-sqrt(13)-1

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x^{2} + 2 x - 12 = 0

x = 13 - 1, x = - 13 - 1

Decimal

x = 2.60555 \dots, x = - 4.60555 \dots

Solution steps

x^{2} + 2 x - 12 = 0

Move

12

to the right side

x^{2} + 2 x = 12

Rewrite in the form

(x + a)^{2} = b

(x + 1)^{2} = 13

For

the solutions are

f (x) = a, - a

Solve

x + 1 = 13 : x = 13 - 1

Solve

x + 1 = - 13 : x = - 13 - 1

The solutions to the quadratic equation are:

x = 13 - 1, x = - 13 - 1

x^{2} + 10 x + 23 = 0

u^{2} - 6 u + 8 = 0

- x^{2} + 4 x + 10 = 0

- 8 x + 96 - 4 x^{2} = 0

4 v^{2} + 20 v = 0

What are the solutions to the equation completesquare x^2+2x-12=0 ?
The solutions to the equation completesquare x^2+2x-12=0 are x=sqrt(13)-1,x=-sqrt(13)-1
Find the zeros of completesquare x^2+2x-12=0
The zeros of completesquare x^2+2x-12=0 are x=sqrt(13)-1,x=-sqrt(13)-1